Bernoulli Equation Fluid Dynamics

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How to Understand and Derive the Bernoulli Equation

Fluid dynamics is a very complex subject, but can be simplified by making some assumptions. The Bernoulli Equation describes the behaviour of incompressible, non-viscous fluids and is a useful way of approximately modeling the behaviour of fluids.

Here is a simple explanation of how the Bernoulli equation is derived, an introduction to fluid dynamics and some applications of it's use: How does an aerofoil work? (i.e. how does a aeroplane fly?) and why does a baseball, cricket ball or tennis ball etc. swing: follow a different trajectory to a non spinning ball (The Magnus Effect)?

Fluid Dynamics

Streamline Flow

Fluid Dynamics: Assumptions

To analyse fluid dynamics there are several assumptions that can be made to greatly simplify the maths:

  • The fluid is incompressible (i.e. constant density)

  • The fluid is non-viscous

  • Angular momentum is ignored (i.e. the fluid is "irrotational")

  • The flow is laminar or streamline and steady (smooth flow without turbulence)


  • These are all fairly unlikely in real life, but this is a good approximation

    Physics Books: Fluid Dynamics

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    The Equation of Continuity

    Conservation of Mass

    Bernoulli Equation

    Applying the law of Conservation of Mass (i.e. what enters a pipe at one end will come out of the other end - assuming no leaks) to the example shown above:

    In time Δt a mass m1 enters the tube of area A1

    m1 = ρ1 A1 v1 Δt

    where ρ1 = density

    a mass m2 leaves A2 at the same time

    m2 = ρ2 A1 v2 Δt

    m1 = m2 (conservation of mass)

    => ρ1 A1 v1 = ρ2 A2 v2

    ρ1 = ρ2 (incompressible fluids)

    A1 v1 = A2 v2

    so as the area gets larger the speed of flow gets smaller and vice versa

    The Bernoulli Equation

    Bernoulli Equation

    Change of speed of a fluid

    Bernoulli Equation

    Applying the law of conservation of energy to the example above (pipe narrowing from Area A1 at pressure P1 to A2 at P2):

    Work done = Work done at A + Work done at B

    i.e. force x distance in time Δt

    W = (P1 A1)(v1 Δt) - (P2 A2)(v2 Δt)

    A1 v1 = A2 v2 =>

    W = (P1 - P2)(A1v Δt)

    Gain in kinetic energy = m(v2^2 - v1^2) / 2 = (A1v1 Δt ρ) (v2^2 - v1^2) = W

    (P1 -P2)(A1v1 Δt) = 1/2 (A1 v1 Δt ρ)(v2^2 - v1^2)

    (P1 - P2) = 1/2ρ(v2^2 - v1^2)

    P1 + 1/2 ρ v1^2 = P2 + 1/2 ρ v2^2

    Bernoulli Equation

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    Bernoulli Equation

    Change of height of fluid

    Bernoulli Equation

    Work Done = gain of potential energy

    (P1 - P2)(Av Δt) = (Av Δt ρ) g (h2 - h1)

    (P1 - P2) = ρ g (h2 -h1)

    P1 + h1 ρ g = P2 + h2 ρ g

    Changing speed and height gives us the Bernoulli Equation:

    P + 1/2 ρ v^2 + h ρ g = constant

    1/2 ρ v^2 = dynamic pressure

    P + h ρ g = static pressure

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    How Does and Aircraft Wing Work? Why Does a Spinning Ball Swing?

    Applications of Bernoulli's Equation

    How Does and Aircraft Wing Work?

    How Does and Aircraft Wing Work?

    An aerofoil creates lift as it moves through the air and this lift can be explained by the Bernoulli Equation:

    The shape is such that the air travels further over the top of the wing and therefore faster

    v1 > v2

    P + 1/2 ρ v^2 + h ρ g = constant

    so P1 < P2

    Why Does a Spinning Ball Swing?

    A ball with "top-spin" (e.g. a tennis ball, baseball or cricket ball) will not follow the expected parabolic trajectory, because the pressure on either side of the ball is different in the same way as the aerofoil example above. This is because the ball is spinning and not because of it's shape.

    On one side of the ball travelling at a velocity v the surface is travelling at v+v' and the other side v-v' where v' is speed of the surface of the ball. i.e. the air moves over the surface at different speeds and from the Bernoulli equation there will be a difference in pressure. This is called The Magnus Effect

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    • gypsyman27 Oct 21, 2011 @ 5:26 pm | delete
      I'm surprised to see a lens involving the bernoulli equation and fluid dynamics. You are a surprising man. I am an engineer, so I am thoroughly familiar with these equations and their use. Really good job of explaining for the layman. Stay well and happy. See you around the galaxy...
    • AndyPo Oct 23, 2011 @ 12:32 pm | delete
      Thanks very much. Yes, perhaps this is not a typical Squidoo lens, but it is a subject that I find fascinating.
    • Philippians468 Jan 23, 2011 @ 10:38 am | delete
      i learnt a thing or two from your lens! great job! cheers
    • Margo_Arrowsmith Dec 3, 2010 @ 5:22 am | delete
      You explained it well. Whether I got it is something else.
    • poddys Jul 2, 2010 @ 3:34 pm | delete
      Too complicated for me, but a great lens Andy.

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