Graphing Linear Inequalities and Solving Systems of Linear Inequalities
This lens is for students, parents and teachers looking for help and ideas on how to graph linear inequalities. It includes examples of solving systems of linear inequalities as well. The primary teaching method is the use of video examples. The best way to use this lens is to work through the examples and then watch the videos to see if you did the problem correct. To find the topic you are looking for scroll down or use the table of contents below.
If you are a teacher looking for resoureces check out my math teaching website. There are some very good worksheets.
If you are a student and looking to get all of your math help in one place this math learning site is for you.
Though I think this lens is valuable and can really help you understand linear inequalities sometimes it isn't enough.
If you are a teacher looking for resoureces check out my math teaching website. There are some very good worksheets.
If you are a student and looking to get all of your math help in one place this math learning site is for you.
Though I think this lens is valuable and can really help you understand linear inequalities sometimes it isn't enough.
Mr. T on Squidoo and the Web
- Inequalities
- My video tutorial lens on solving single variable inequalities.
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- Simplifying Square Roots
- A lens showing how to multiply, divide, and simplify square roots.
- Solving Quadratic Equations
- A lens showing how to solve quadratic equations.
- Polynomials
- A lens showing how to add, subtract, multiply and factor polynomials.
Linear Inequality Worksheets
- Video Examples
- This is a worksheet with some of the video examples from this lens and then lens on inequalities.
- Basic Linear Inequalities
- Four basic linear inequalities accompanied by graphs.
Graphing Linear Inequalities
When graphing linear inequalities it is important to first graph the line as if it was an equation. For example:
If the problem was y > 2x + 3 then you would graph y = 2x + 3. There are various ways to graph lines. Here are some examples:
http://www.purplemath.com/modules/strtlneq.htm
http://www.coolmath.com/algebra/Algebra1/06Lines/04_intercepts.htm
Before you actually graph the line it is important to look at the inequality sign. There are two possiblities:
1) Less than (<) or greater than (>). In this case you the graph of the line needs to be dotted.
2) Less than or equal to and greater than or equal to. In this case the graph of the line needs to be solid.
After you have graphed the line (dotted or solid) it is then important to shade one side of the line. This is done because on one side of the line all the points make the inequality true and on the other side all the points make the inequality false. The solution to the inequality is all the points that make it true.
To do this you must test a point. If that point makes the inequality true, all the points on that side of the line are true. If it make the inequality false, then all the points on the other side of the line are true.
Procedure
1) Pick a point NOT on the line ( (0,0) is a good choice if possible).
2) Substitute the point in for the original inequality. Evaluate if it is a solution or not.
3) If it is a solution shade in the side the point is on. If it is NOT a solution then shade in the other side.
If the problem was y > 2x + 3 then you would graph y = 2x + 3. There are various ways to graph lines. Here are some examples:
http://www.purplemath.com/modules/strtlneq.htm
http://www.coolmath.com/algebra/Algebra1/06Lines/04_intercepts.htm
Before you actually graph the line it is important to look at the inequality sign. There are two possiblities:
1) Less than (<) or greater than (>). In this case you the graph of the line needs to be dotted.
2) Less than or equal to and greater than or equal to. In this case the graph of the line needs to be solid.
After you have graphed the line (dotted or solid) it is then important to shade one side of the line. This is done because on one side of the line all the points make the inequality true and on the other side all the points make the inequality false. The solution to the inequality is all the points that make it true.
To do this you must test a point. If that point makes the inequality true, all the points on that side of the line are true. If it make the inequality false, then all the points on the other side of the line are true.
Procedure
1) Pick a point NOT on the line ( (0,0) is a good choice if possible).
2) Substitute the point in for the original inequality. Evaluate if it is a solution or not.
3) If it is a solution shade in the side the point is on. If it is NOT a solution then shade in the other side.
Important!
Don't Forget!!!
Greater than or less than is a dotted line.
Greater than and equal to or less than and equal to is a solid line.
Greater than and equal to or less than and equal to is a solid line.
Graphing Linear Inequalities Example 1
This is an example of how to graph a linear inequality.
curated content from YouTube
Graphing Linear Inequalities Example 2
This is an example of how to graph a linear inequality.
curated content from YouTube
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Solving Systems of Linear Inequalities
Above we learned how to graph the solution of a linear inequality. Now we move onto problems involving more than one inequality. Particularly we are going to look at systems of two inequalities.
The solution to a single linear inequality is all the ordered pairs (x, y) that make the inequality true. It is usually designated by a shaded region on a graph.
For a system of linear inequalities you are looking for all the points that make both inequalities true. This is done by graphing both inequalities and then looking to see where the shaded regions overlap. The overlap is the solution to the system. The procedure for solving these problems is:
1) Graph the first linear inequality. Shade the answer lightly using a horizontal pencil stroke.
2) Graph the second linear inequality. Shade the answer lightly using a vertical pencil stroke.
3) Identify the region where the two solutions overlap. Shade this region in darkly and then indicate it as the solution of the system.
The solution to a single linear inequality is all the ordered pairs (x, y) that make the inequality true. It is usually designated by a shaded region on a graph.
For a system of linear inequalities you are looking for all the points that make both inequalities true. This is done by graphing both inequalities and then looking to see where the shaded regions overlap. The overlap is the solution to the system. The procedure for solving these problems is:
1) Graph the first linear inequality. Shade the answer lightly using a horizontal pencil stroke.
2) Graph the second linear inequality. Shade the answer lightly using a vertical pencil stroke.
3) Identify the region where the two solutions overlap. Shade this region in darkly and then indicate it as the solution of the system.
What Every High School Student Needs!!!
A graphing calculator is essential in an Algebra, Pre-Calculus and Calculus classroom.
System of Linear Inequalities-Special Case
In this video you will see what happens when the two lines being graphed are parallel.
curated content from YouTube
Systems of Linear Inequalities - Special Case Example 2
In this video you will see what else can happen when the two lines are parallel.
curated content from YouTube
Math Help on Amazon
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blackspanielgallery
Feb 27, 2011 @ 1:27 am | delete
- Why restrict to linear?
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Paula
May 1, 2009 @ 10:27 am | delete
- You are the best!!!!!!!Thanks for your help!
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shawn michaels
Jul 27, 2008 @ 8:11 am | delete
- how do you solve this equation
7x6
y<5
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cel
Jul 18, 2008 @ 8:29 pm | delete
- this is easy to understand thanks. but i was gven a graph and the teacher wants us to write the inequaltiy of the graph. its like vice versa.. if you have time maybe you can add that to your lens..thanksa alot
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???
Apr 16, 2008 @ 9:12 pm | delete
- this helped me with my homework alot thanks.
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Student
Feb 5, 2008 @ 9:54 pm | delete
- Thank you so much for this help. I have a horrible teacher who I don't learn a thing from and this was really easy to follow. Thank you so much!!!
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flaminglacer
Jan 19, 2008 @ 1:28 am | delete
- Brought back memories! Squid Angel blessing
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by MrT68
MrT68
My name is Trent Tormoehlen and I am a math teacher at Sycamore School in Indianapolis Indiana. I will also be helping coach the schools Math Counts... more »
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