Einstein's Special Theory of Relativity - An Easy (I hope!) Explanation
Ranked #203 in Education, #4,771 overall
Some weird aspects of Special Relativity explained
Are you curious about relativity theory? What I mean is, are you fascinated by the bizarre effects that relativity predicts and want to genuinely understand why nature behaves this way? While relativity is not a light read (all puns here are accidental, BTW), parts of it can be readily comprehended. This is particularly true of Special Relativity.
I'll try to give an informal and intuitive account of why the passage of time for a rapidly moving object appears to slow down. That is, why something which is traveling very rapidly relative to you would appear to age very slowly.
Two things that you'll have to accept without further explanation is that light travels at a constant speed (an experimental fact) and that everyone's point of view (or frame of reference moving at constant speed) is equally legitimate. Everything else will follow logically from this.
I know that my lens title implies that a complete account of relativity will be given. Unfortunately that is beyond what I can accomplish here. I don't mean to frustrate any of the super left-brained types out there with my informality. Don't let those logic circuits to get fried over this! I don't want this to read like a page out of a physics school text.
I have tested this explanation with my non-geek brother and he understood it right away.
I'll try to give an informal and intuitive account of why the passage of time for a rapidly moving object appears to slow down. That is, why something which is traveling very rapidly relative to you would appear to age very slowly.
Two things that you'll have to accept without further explanation is that light travels at a constant speed (an experimental fact) and that everyone's point of view (or frame of reference moving at constant speed) is equally legitimate. Everything else will follow logically from this.
I know that my lens title implies that a complete account of relativity will be given. Unfortunately that is beyond what I can accomplish here. I don't mean to frustrate any of the super left-brained types out there with my informality. Don't let those logic circuits to get fried over this! I don't want this to read like a page out of a physics school text.
I have tested this explanation with my non-geek brother and he understood it right away.
Why relativity seems so bizarre
Our brains are wired for survival purposes for a 3 dimensional and very slow moving environment. Compared to the speed of light, the everyday objects that our brains perceive and reason about are barely moving at all. Our common sense about how the world works is specialized for dealing with an almost non-moving or static environment (again, that's compared to the speed of light).What this means, is that what our common sense tells us about our sluggish everyday world is mostly correct but otherwise it's judgements cannot be trusted when dealing with extremely fast things.
So when experiments and mathematics tell us things that are contrary to our crude perceptions about how things should work, we find it to be totally bizarre!
The speed of light...a 19'th century enigma

Our everyday common sense tells us that if while standing on a moving barge we hit a golf ball off the front, the speed of the barge adds to the speed of the golf ball. If we were to shine a flashlight in the same direction as we had hit the ball we would find that the speed of the barge does not add to the speed of the light beam. Its speed would be the same as if the barge were not moving at all.
The best minds of the 19'th century were stumped by this fact because it totally violated a very basic and seemingly self evident notion of how things are supposed to work.
In 1905, Einstien explained that this was simply the way that light behaved and that it only seemed strange because our common sense notions of how relative speeds were supposed to add up were only true for very slow moving objects (as compared to the speed of light).
Interestingly, the theory of electromagnetism, developed in the 19'th century by James Clerk Maxwell, also predicted this fact that the speed of light was unaffected by the speed of its source.
Note: In this explanation I'm trying to avoid excessive 'relative to this, relative to that' verbiage. Unfortunately, this can leave things somewhat vague. In the golf ball example above, to someone watching from the shore, the golf ball appears to move at a speed equal to the speed of the barge plus the speed of the ball relative to the barge. Our common sense says that this should be true regardless of how fast the ball leaves the barge. However, this doesn't hold up if we do the same experiment with a beam of light.
Why time slows down
So the speed of light is unaffected by the speed of its source. Let's see what falls out of this...Imagine having two horizontal mirrors facing each other and that one mirror is spaced above the other by the distance d. Also imagine that there is a pulse of light that bounces vertically between the two mirrors as shown in the left part of the drawing below.
The time it takes for the pulse of light to do a round trip (from the top mirror to the bottom mirror and back to the top) is twice the distance d divided by the speed of light. This device would actually make a great clock since the pulse can be relied on to always travel at the same speed while doing its round trips and thus always counting out consistent time intervals.

Suppose our "light clock" were traveling sideways at a very high (but constant) speed. Now the pulse would follow the "saw tooth" path shown on the right side of the drawing. The light must travel a greater distance now to make a round trip. Since its speed is the same as before (remember, the speed of light is not changed by the speed of its source), it will take longer to make a round trip.
So our "light clock" takes longer to count out its intervals. Another way of saying this is that the clock "ticks" more slowly.
Note that if the speed of light were not constant, the horizontal speed of the clock would have added to the speed of the pulse. Then, the light clock would not have slowed down since the pulse's greater speed would have compensated for the longer distance of the "saw tooth" path.
Stifle that yawn. This result has great significance as I will explain in the next section.
The "relative" part of relativity

Suppose you are the person who is taking this photo and the other guy seems to be drifting toward you. Are you moving toward him or is he moving toward you? The answer is yes to both questions.
From each person's point of view, he is stationary, and the other guy is moving. Relativity states that everyone's frame of reference is valid. The observations that you make from your frame of reference is just as valid as those made by some one else on a different reference frame.
Now, back to the light clock... It's very feasible to hook up the light clock to an LED display that reads out seconds, minutes, and hours. Now lets say you choose a frame of reference that's "stationary." That way you get a clock that's keeping time "properly" (don't want a slow running clock, thank you very much!) So your light clock is behaving like the one on the left side of the drawing above.
But as always, someone comes along (at an extremely fast speed) to spoil your day. From his point of view, you're the guy that's moving, not him. From his equally valid point of view, your light clock is behaving like the one on the right side of the drawing above. And of course, to him your clock is counting out its intervals very slowly and your LED is counting out those seconds, minutes, and hours way too slow. Since you're stationary relative to your clock, it's working just fine as far as you are concerned. Now you try to tell him this and you speak at a normal rate (about 4 words/second by your clock). To him you are speaking 4 words/second relative to your very very slow clock. You sound like an old fashion phonograph record that is set to a very slow speed.
And of course since he is moving relative to you, his speech sounds equally slow.
This effect is called time dilation.
Time dilation is present even at the slow speeds that we are used to. But it's so tiny that our senses can't detect it. 60 miles/hour or even 3000 miles/hour is too slow compared to the speed of light at 186,000 miles/second or 669,600,000 miles/hour. At 60 miles/hour the triangles in the drawing above would have such a tiny base that they wouldn't look any different from the vertical photon path of the stationary clock. So the stationary clock and the 60 miles/hour clock "practically" keep the same time.
Addendum - Light Clock Clarification
In the section that describes how the light clock works I wrote:
"Suppose our light clock were traveling sideways at a very high (but constant) speed. Now the pulse would follow the "saw tooth" path shown on the right side of the drawing."
I omitted an explanation for why the pulse would follow a saw tooth pattern. This prompted the following question from a reader:
"If the speed of the boat does not add to the speed of the photon, then when we move our light clock sideways, the photon should not zig zag, but go straight down and miss the bottom mirror."
"Suppose our light clock were traveling sideways at a very high (but constant) speed. Now the pulse would follow the "saw tooth" path shown on the right side of the drawing."
I omitted an explanation for why the pulse would follow a saw tooth pattern. This prompted the following question from a reader:
"If the speed of the boat does not add to the speed of the photon, then when we move our light clock sideways, the photon should not zig zag, but go straight down and miss the bottom mirror."
Here is the explanation:Suppose the two mirrors were on a very fast moving boat and a flash bulb on the bottom mirror emits a brief flash of light that propagates outward. To someone riding on the boat, the light flash would expand away from the bulb at the speed of light. He would describe this as an expanding hemisphere of light (diagram). From his point of view, the light source is not moving, so to him, the expanding hemisphere would always be centered about the flashbulb.
This person would see that any light that's captured by the two mirrors would be bouncing up and down between them. There would be no saw-tooth pattern.
Someone watching from the shore would see a different scene. He would not see the hemisphere of expanding light moving along with the boat. That's because the light would be moving faster than c on the leading surface of the hemisphere and slower on the trailing surface. This is not allowed by relativity.So the person on the shore would see a stationary hemisphere of expanding light. To him, the boat (and it's two mirrors) would be moving away from the center of this hemisphere (the mirrors are moving toward the left in the diagram).
To him, light that's moving straight up would miss the top mirror. The two mirrors would only capture light moving along the diagonal path shown in the diagram. The light would appear to bounce between the mirrors in a zig-zag or sawtooth pattern.
We're at the end of the explanation here. However, you might be wondering how it is that the light hemisphere can be stationary with respect to the person on the moving boat and the person on the shore. These two people are moving relative to each other so it seems to be a contradiction. This paradox arises from the requirement that the speed of light remain constant to all observers which itself seems paradoxical.
There is no explanation for this that your intuition or common sense will readily grasp. As was mentioned at the beginning of this lens, our brains are wired to function in a very slow moving 3D spatial environment.
The only way to "understand" this paradox is by turning to abstraction and introducing a four dimensional abstract (or real?) space called space-time. If this interests you click here.
Reader Feedback
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goo2eyes
Feb 12, 2012 @ 9:32 am | delete
- this lens is well-deserving of the purple star. i'm sorry but my left and right lobes of the brain can't grip all of your explanations all i know is that if i travel with a plane which is travelling beyond the atmosphere-ozone layer, i can reach my destination earlier than if i use the regular flight. the magnetic fields prevent the objects from travelling so fast. i think i missed the point, huh? angel blessings.
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Marc_Sandford
Feb 13, 2012 @ 8:59 am | delete
- Hmm, let me think about that... :-)
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Pangionedevelopers
Jan 28, 2012 @ 11:51 pm | delete
- congrats on your award
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Marc_Sandford
Jan 29, 2012 @ 9:24 am | delete
- Thank you!
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couch
Jan 6, 2012 @ 6:30 pm | delete
- Hi Marc, thanks for answering all the questions, its a great read. Sorry if these questions have been asked previously, simply point me your post if I am duplicating anything. I have a couple of questions if I may:
The light-pulse clock makes sense when you are travelling horizontal to the clock which is pulsing vertically (say North south for ease), but what happens if the other observer is travelling due south away from the clock (or relatively speaking clock is moving north)?
It will appear that the north-travelling pulse will take longer to reach the top than it would for the south-travelling pulse to return back to the bottom. Or am I missing something?
You also said that time dilation is a perspective phenomenon, it just "appears" that time goes slower to the observer. In other words time isnt really going slower its just an optical illusion because it takes longer for the light to reach the observer?
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Marc_Sandford
Jan 7, 2012 @ 10:25 am | delete
- That's equivalent to tipping the light clock in the above example on its side. I'm sorry that I won't be able to give you an answer using simple geometry because the length of the light clock apparatus (distance d in the above diagram) will contract thus complicating things. In such an orientation, we are now dealing with length contraction and time dilation together. Length contracts in the direction of movement. Length remains unchanged if it is orthogonal to the direction of movement. That is why most discussions of time dilation using light clocks orient the clock at right angles to the direction of motion.
If you accept that the spatial orientation of a clock won't affect its period or "tick-tock time" (please don't mention pendulum clocks in a place that has gravity) such as your watch floating at an arbitrary orientation, then the orientation used in the above example (at right angles to the direction of motion) is a "good enough" explanation of time dilation. It has the advantage of simplicity in that time dilation occurs without the complication of length contraction. This simplicity also makes it quite easy to derive an equation for time dilation. Just compute the distance "d" in terms of the speed of light and time from the point of view of both observers and then equate both expressions (since distance "d" is the same for both observers).
I recommend reading this. Go to the section called "Derivation of length contraction". Note that Fig. 7.3 on that page is the light clock tipped on its side. In that section he derives an expression for length contraction using an expression for time dilation developed in the previous section (where the light clock is standing upright).
That should answer the "what happens" part of your question. The answer is yes to your next question about whether the return time of the light pulse is different from the time it takes to reach the mirror opposite the pulse gun.
I mentioned that time dilation is a perspective phenomenon in four dimensional space-time. I should say that it is analogous to the phenomenon of perspective in three dimensional space. It's just a useful way of thinking about it. Nothing more. Time dilation is not an illusion (ie something that tricks the mind into perceiving something that isn't there or some other false relationship). It is real in that everyone measures it, technology is affected by it, and it is a logical outcome of the fact that the speed of light is constant and that the laws of physics are the same for all (non accelerating) frames of reference.
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Marc_Sandford
Jan 7, 2012 @ 8:16 pm | delete
- One other point. The explanation for time dilation given in the light clock section above, makes no reference to the time lag for the light to reach the observer. Therefore time lag plays no part in time dilation.
If the proof for the Pythagorean theorem makes no reference to the positions of the planets, then the positions of the planets play no part in the Pythagorean theorem. I'm being something of a wise guy, but using this kind of logic will greatly accelerate the learning process.
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Tolovaj
Jan 3, 2012 @ 5:54 am | delete
- Thank you for detailed explanation. I think I'll have to check back to read it again. The concept of connection of time and other dimensions is pretty hard to chew down. I did some exams of quantum mechanics but emphasis was on math, not plain logic. Still have to work on it:-)
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waldenthree.net
Jan 1, 2012 @ 11:23 am | delete
- Important topic for science and enginering people ! Congrads on reaching Squidoo 100 list. Going for next Squidoo level 55. See you soon again soon. Thanks.
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hector_sam101
Dec 24, 2011 @ 12:37 pm | delete
- Marc,
The questions i asked was my effort to understand relativity better...
I appreciate your knowledge on this particular subject, but the way gave the response was
rude and disappointing.
I could see that my question and your response to that have been removed. Not sure if you did it for keeping your post with comments that supports and appreciates your matter of interest only.
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Marc_Sandford
Jan 1, 2012 @ 7:59 pm | delete
- Yes, my response was rude and it took me a few hours to realize it. I took it down because I didn't like the way that I responded to your question. I do censor rude comments including my own.
The reason that I reacted in this way is because I get lots of comments from people trying to redefine Einstein's theory. Relativity seems to be a magnet for revisionists (for lack of a better term), armchair physicists, and new age mystics. These are people who have their own version of the theory that makes sense to them. Some even deny that it's real. Many of these people feel it's their right to have their point of view expressed here. It's not going to happen. Not on my lens. Allowing these types of comments only serves to confuse visitors who want to grasp the explanation given here. Allowing these comments means that I will have to refute every one of them and give a complete explanation as to why they are incorrect. This means getting into their thinking process to point out where they are in error. Doing this is too costly in terms of time and effort. Defending Einstein wasn't the reason for putting up this lens. I don't have the time for that. Defending Einstein shouldn't even be necessary, given the countless ways that it has been verified by the scientific establishment. How people can deny it or modify it in the face of this is beyond my comprehension.
I'm only open to providing explanation to points that my viewers want clarification on. You are 100% correct in your assertion that do I pick and choose which comments to reply to. Do I do it in a way that supports my interest? Yes. Absolutely. What is my interest? It's providing explanation to points that my viewers want clarification on. It's viewers who implicitly accept relativity even though they don't understand it yet. Those are the viewers that I respond to.
Sometimes I simply have no time to respond even to legitimate questions (as I have already defined). Too many other things that I must do, so I just can't respond. I have put work into this lens. People benefit from this even if I don't respond to all of the comments. So that's not such a terrible thing.
You must realize that the principles of physics don't get decided by popular opinion. If that were the case, it wouldn't be science. It would be something else. Science does evolve and change but it only allows people with certain qualifications using a certain methodology to do this. It is this fact that turns off many people to science because it isn't egalitarian enough for them. But you can't deny that it works quite well, especially when you consider the amazing technology that has spun off from it. Did you know that your GPS device in your car or cell phone makes allowances for relativistic effects? They (relativistic effects) must be real given the accuracy of these devices.
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Chris-H
Dec 4, 2011 @ 11:27 pm | delete
- Thanks for your explanation on a not-so-easy-to-explain topic. Of course Einstein's buddy Kurt Godel would have questioned the whole notion of time altogether. An interesting discussion!
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Marc_Sandford
Dec 5, 2011 @ 9:21 am | delete
- Thanks. Looking forward to reading your lens on Kurt Godel. I've read a lot about him and the incompleteness theorem.
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chithukkutty
Nov 20, 2011 @ 1:47 pm | delete
- lovely visual example
is it because of relativity or persistence of vision the light appears stretched?? to an observer?
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ssangweni
Nov 21, 2011 @ 8:51 am | delete
- Very good question.That's what have been trying to get an answer to.To me it sounds like this is just persistence of vision.
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Marc_Sandford
Nov 21, 2011 @ 9:38 am | delete
- It has nothing to do with the after images associated with human vision (persistence of vision). This question has been brought up before and is explained in the comments below.
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chithukkutty
Nov 21, 2011 @ 12:50 pm | delete
- thankyou!
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sanstar
Dec 1, 2011 @ 4:19 am | delete
- I have a question on the constancy of the speed of light:
1. If we travel at the speed of light (300,000 kms/s) and measure the light's speed, still we will measure it as 300,000 kms/s. Is this because our perception of space and time has changed at that speed? That means, if we are to reach our destination "X", we will not reach at the same time? The time of course has diluted but also the distance perception has changed?
2. If we go beyond the speed of light (imagine), will time flow back at that speed?
Thanks
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Marc_Sandford
Jan 7, 2012 @ 8:25 am | delete
- Yes our measurements of length and time will change to accommodate the constancy of the speed of light. If our perceptions and our measurements of time and space change, then we may as well say that time and space has changed. Sorry it took so long to answer.
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chithukkutty
Nov 20, 2011 @ 1:40 pm | delete
- hey !! :) interesting discussions down here!! :) thank you so much for answering my previous questions!!
well, ive been reading about planets in our universe and one question popped up !
i kno its unrelated to relativity but i thought you could help me!!
my question is,
DOES THE GRAVITY/ SIZE OF A PLANET PLAY A MAJOR ROLE IN ITS CAPACITY TO SUPPORT LIFE??
IT WOULD BE WONDERFUL IF YOU CAN ANSWER THIS QUESTION!!!
fingers crossed!!
thank you
-chitra
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Marc_Sandford
Nov 21, 2011 @ 8:54 am | delete
- Until scientists can study actual examples of extraterrestrial life it will remain a topic of conjecture. Scientists say that simple life can exist in a variety of circumstances. All that's required is that the chemistry of the environment support life and that there is an energy source that can be tapped. I would think that microbial like life wouldn't care about the size of the planet whether it is floating around in the atmosphere of a gas giant or is living deep inside the liquid water of Europa (a moon of Jupiter). However, once you have the right ingredients for life there is still the matter of how it kick starts itself in that environment.
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molometer
Nov 12, 2011 @ 7:35 pm | delete
- Interesting. I got it. Thanks
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Serthy
Jun 26, 2011 @ 11:13 am | delete
- Hey, i have a question, not directly conserning this toppic, but you seem to have gotten alot of questions about everything allready, so i thought i should atleast try it.
Here is the problem:
If you (for simplicity) are flowting "stationairy" in space and there is an (to you) moving object very large distant away (the "object" is not coming directly towards you nor moving directly away from you, just passing away). And lets say now, you would want to have some fun with your laser! So you want to hit the "object" with the laser.
My problem now is... the light from the laser would take atleast some light-seconds/light-years (or whatever, the important thing is that it's a great distance). So where would i then aim my laser? do i calculate the time it takes for the light to get there and compare it to where the object will be at that particullar time? the only logic explenation i can figure is that you aim it directly at the object.... but where would it then hit the object? Becauce during the time it takes for the light to get there, the object will have moved a great deal.
So the question stands... Where should i aim my laser? Silly question and maybe i'm just to dumb to see it, but i'd appreciate an answer ^^
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Marc_Sandford
Jun 28, 2011 @ 1:21 pm | delete
- ........................................T2
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....................T1................
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T0................................
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Hi. In the diagram above, the laser gun is point G. The apparent position of the target that you actually see is point T0. But point T0 is 100 light years away so that is where it was 100 years ago. Point T1 is where it really is right now. Now you can't fire your laser gun at point T1 because your target won't be there when the laser beam arrives.
Now I'm going to make this problem as simple as possible so that my answer doesn't get too lengthy. There are no other masses around that exert gravitational effects. The target is moving at a constant velocity relative to the gun. The gun operator knows the targets postition T0. He also knows the speed of the target and the direction of motion of the target.
Some definitions of symbols:
the speed of the target will be v
the speed of light will be c
the distance between G and T1 will be D
the angle (G, T1, T2) will be w
The gun operator can calculate where T1 is because he knows the position, speed, and direction of motion of the target. He knows that the target has been traveling for 100 years (since T0 is where it was 100 years ago ). So the distance between T0 and T1 is equal to the speed v times 100 years.
The gun operator will aim the gun ahead of T1 at point T2 which is the intercept point. This is where the target and the laser beam meet at the same time. We don't know what this time is yet so we will just call it time t. If you can figure out what this time interval is then you can figure out two of the sides of triangle G, T1, T2. The third side is easily computed (as shown in the next paragraph). Once we have the sides of the triangle, we can get its angles. This will then give us the angle for aiming the laser.
We know the postion of T0. We know the heading vector (direction of motion) of the target. It moves along that vector for a distance of v times 100 years. This gives us the coordinates of T1. We can now compute the distance between G and T1 using the coordinates of both points. This distance will be called D.
Now we will figure out the interception point T2. The lengths of the sides of triangle G, T1, T2 are:
side (G,T1) has length D
side (T1,T2) has length v times t or vt. where v is the speed of the target. t is the time of travel between T1 and T2 which we don't know yet.
side (G,T2 ) has length c times t or ct. where c is the speed of light (which of course is the speed of the laser beam). t is also the time it takes for the laser to reach T2.
We know the position of T1. Therefore we know its direction relative to G. We also know the direction of T2 relative to T1 because we know the direction of travel of the target. From this information we know the angle (G, T1, T2). We will call it w.
We can now use the law of cosines on triangle G, T1, T2 to set up an equation that can be solved for time t.
(ct)^2 = D^2 + (vt)^2 - 2D(vt)cos(w)
cos(w) is the cosine of w
^2 means squared
This gives you a quadratic equation in t. t can be solved using the quadratic formula. You will get two answers for t. One will be positive and the other negative. This problem was formulated for positive values of time so the postiive answer is the only one you can use.
Now that you have the travel time of the object (which is also the travel time of the laser beam) you know all three sides of triangle G, T1, T2. From this you can get the angle for aiming your laser gun.
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Marc_Sandford
Jun 28, 2011 @ 1:32 pm | delete
- Above, I wrote "The gun operator can calculate where T1 is because he knows the position, speed, and direction of motion of the target."
That is confusing. I should written "The gun operator can calculate where T1 is because he knows the position T0, the speed, and direction of motion of the target."
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Marc_Sandford
Jun 28, 2011 @ 2:25 pm | delete
- The diagram is not drawn to scale. It's just the equivalent of a sketch to facilitate the explanation. So no, the target is not going faster than the speed of light.
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Marc_Sandford
Jun 29, 2011 @ 12:52 pm | delete
- This solution can be streamlined by using the law of cosines on the triangle G, T0, T2
the length of side (G, T0) is already known (100 light years). This known quantity will be given the symbol L.
side (T0, T2) has length vL/c + vt
side (G, T2) has length ct
we also know angle (G, T0, T2). we will call this angle Q
use law of cosines:
(ct)^2 = L^2 + (vL/c + vt)^2 - 2L(vL/c + vt)cos(Q)
solve for t and use positive answer.
you now have t which means you can evaluate the lengths of all three sides of the triangle. this gives you its angles. now you know the angle (T0, G, T2) which is the firing angle for the laser gun.
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ssangweni
Jun 13, 2011 @ 10:25 pm | delete
- Relativity has always fascinated me but it also has mightily confused me.I have 2 problems with the expalnation, and I am sure that's because my mind is too small to digest.But, here goes:
In your explanation(of the slowing dowon of time) using the vertical beam of light, it indeed appears as though the beam of light travels a longer distance when the rocket is in motion and, yes, time seems to slow down(I have another issue this, but for a later time).
However, suppose the clock being using is not a vertical beam, but one inclined at an angle in a direction opposite to the motion of the rocket.
[I am assuming the oriention or appearance of the timing device does not matter].
Now, with rocket stationery, the outside observer should see a "saw-tooth" shaped beam of light, right?But, as soon as we move the rocket, we can choose to move it at a certain constant speed where the beam appears to be vertical to the outside observer.At this speed, time seems to have speeded up since the (now, apparently)vertical beam is travelling a lesser distance!Which is a total contradiction to the state of affairs to where we start with a vertical beam.
I am sure you have been asked this question before but I have never been fully answered on this one.
As soon as you answer this one, I will give you my next question.
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Marc_Sandford
Jun 15, 2011 @ 8:02 am | delete
- So you tilt the light clock back a bit so that as the pulse travels to the top mirror, it's horizontal motion is canceled out by the motion of the rocket. This would make the pulse move vertically as it travels toward the top mirror (as seen by the stationary observer).
Now, when the rocket is stationery relative to the outside observer, both observers would see the same thing since both of them are now stationary relative to the clock. They would both see a simple straight line that is tilted back a bit.
Now make the rocket move at a speed that causes the pulse to appear to travel vertically as it goes to the top mirror (as seen by the stationary observer). Now the pulse reaches the top mirror and bounces back toward the bottom mirror. As it moves toward the bottom mirror, its horizontal motion component as seen by the observer in the rocket is now in the same direction as the rockets motion. At this point, the rockets motion does not cancel the horizontal component of the pulses motion. In fact, the two add together which means that the pulse is moving diagonally from the point of view of the stationary observer. So the stationary observer sees the pulse moving vertically towards the top mirror and then diagonally on it return to the bottom mirror.
I'm going to stop here and repeat what I said from the point of view of the guy in the rocket. He makes the rocket move at a certain speed. He observes the light pulse going back and forth between the two mirrors. To him, the beam path is a simple line that is tipped back a bit. When the pulse moves toward the top mirror, it horizontal motion component is equal but opposite to the motion of the rocket. After the pulse bounces off the top mirror it travels back to the bottom mirror. As it moves toward the bottom mirror, its horizontal motion component is now traveling in the same direction as the motion of the rocket.
At this point, the motion of the rocket no longer cancels the horizontal motion component of the pulse (it adds to it). The cancellation occurs only when the pulse moves to toward the top mirror. It does not occur when it travels to the bottom mirror.
So from the point of view of the stationary observer, the pulse moves vertically towards the top mirror and then diagonally on it return to the bottom mirror. This is a saw tooth pattern that has teeth with a vertical leading edge and a diagonal trailing edge (or vice versa depending on how you want to define "leading and trailing" edges).
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Marc_Sandford
Jun 15, 2011 @ 7:29 pm | delete
- Hi there. I posted a well thought out answer to your question and somehow squidoo lost it. Sorry about that.
In my answer, I am going to use some basic vector terminology. Velocity is a vector. Vectors can be split up into components. In the light clock example, the light pulse velocity will be split up into a horizontal component (parallel to the rockets motion) and a vertical component.
An example of vector usage: a person walking 5 mph in a northeast direction could be thought of as moving 3 mph towards the north and 4 mph toward the east. If he proceeds to go due north, then he is moving 5 mph toward the north and 0 mph toward the east.
My apologies if you are already familiar with vector use.
So we have a light clock that is tilted back. This will cause the light pulse to have a horizontal velocity component that is opposite to the direction of the rocket's motion when the pulse is moving toward the top mirror. Now we adjust the speed of the rocket so that the rocket velocity is equal but opposite to the horizontal velocity component of the light pulse (as the pulse moves toward the top mirror). This makes the pulse appear to be moving vertically upwards from the point of view of the stationary observer.
So far so good, however...
After the pulse bounces off the top mirror it then heads back to the bottom mirror. Now its horizontal velocity component has reversed itself and is in the same direction as the rockets motion.
Now to recap:
When the pulse moves toward the top mirror, its horizontal velocity component is equal but opposite in direction to the rockets motion and so gets canceled out. This makes the pulse travel vertically from the point of view of the stationary observer.
When the pulse goes back to the bottom mirror, its horizontal velocity component is in the same direction as the rockets motion. This means the rockets velocity adds to the horizontal velocity component of the pulse. This makes the pulse appear to travel in a diagonal from the point of view of the stationary observer.
When you put the two paths together: vertical and diagonal, you get a saw tooth pattern. One side of the tooth is vertical and the other side is diagonal.
So the pulse still follows a saw tooth path from the point of view of the observer. This saw tooth path is a greater distance than the (tilted) straight line path seen by the guy in the rocket. And the stationary observer sees the clock "ticking" more slowly. By the way, I compared the saw tooth length against the tilted straight line and the saw tooth is in fact longer. Some geometry and algebra shows this.
Of course, the easy answer to your question is that if the principle is shown to be true in one orientation it must be true in all orientations. Demonstrating this is just an exercise in geometry or vector analysis (which was my approach here).
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Marc_Sandford
Jun 15, 2011 @ 7:32 pm | delete
- It looks like the first explanation is back. So you get two versions!
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ssangweni
Jun 15, 2011 @ 10:40 pm | delete
- Thank you very much for the response.The vector version makes it more clearer.
I am still puzzled though.
Here's where we agree:
The tilted beam, on its way to the top mirror, has 2 components: one pointing vertically towards the mirror and the other pointing horizontally in a direction opposite the rocket motion.So at a certain speed, the horizontal comp. will cancel out with the speed of the rocket and the stationary observer will see a vertical beam during the upward cycle.
Here's where I don't agree(or where my confusion is):
As regards the reflected beam, the beam still is tilted in such a way that it strikes the bottom mirror at a point even further behind the apex(where it struck the top mirror).If you break this vector into its component vectors you will find that only the vertical component has been reversed.The horizontal component didn't change direction at all.It still is against the motion of the rocket.(If you use arrows in your diagram, you will find that the reflected beam's arrow is now facing DOWN.If the arrow is facing down and the beam tilted further back, surely the horizontal component is still opposed to motion of rocket)
This will mean the horizontal motion of the rocket is cancelled by the beam in both cases( going up and down).Therefore the stationary observer should always see a vertical beam.
And a vertical beam is shorter than a saw-tooth.Time speeded up, it seems!
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Marc_Sandford
Jun 16, 2011 @ 6:45 am | delete
- It seems like you are doing your vector analysis on a moving target (that is, the mirror that the stationary observer sees). Do your analysis on the stationary mirror (as viewed by the guy on the rocket) AND THEN work out how each part of the pulse path is seen by the stationary observer. This is simpler than chasing the mirror around in the minds eye. This is the basis of my vector explanation given above.
From the point of view of the guy in the rocket, the two mirror arrangement and the light pulse behavior looks like the straight line path shown in the LEFT DIAGRAM here except that the whole arrangement is tilted. In this diagram the light is reflected back to where it started (and then repeats the cycle over again). In this diagram (when tilted), both horizontal and vertical velocity components are reversed. If the horizontal and vertical components were not reversed, the light would not return to its starting point (again, as seen by the guy in the rocket).
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Harikuttan
Jun 10, 2011 @ 5:57 am | delete
- Note that if the speed of light were not constant, the horizontal speed of the clock would have vectorially added to the speed of the pulse. Then, the light clock would not have slowed down since the pulse's greater speed would have compensated for the longer distance of the "saw tooth" path.
Sorry i couldn't understand this statement
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Marc_Sandford
Jun 10, 2011 @ 7:11 am | delete
- No problem. Imagine a bouncing ball in a car. Inside the car it moves up and down. To someone on the road it follows a saw tooth path. To both observers, the ball takes the same amount of time to complete its bounce. From the roadside observers point of view, the ball is traveling a greater distance along a saw tooth path but it is also traveling faster because the speed of the car adds to the speed of the ball. Even though the ball must travel further, it is also moving faster. So the ball takes the same amount of time to complete its bounce.
If the speed of light were not constant, it would behave like the bouncing ball. Both observers in the light clock example would see the light pulse complete its round trip in the same amount of time. So the clock would not appear to have slowed down.
PlEASE, lets leave out the fact that the ball accelerates and decelerates under the earths gravity, it has nothing to do with the principle being discussed! If you (or any other reader) get stuck on that point, then imagine the ball moving up and down in a slow moving space ship where there is no gravity. Or you can imagine something moving back and forth horizontally on a frictionless table inside the car. Sorry about that. I'm imagining getting lots of comments nit picking on this :)
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Marc_Sandford
May 26, 2011 @ 8:14 am | delete
- I received a comment from a reader that wasn't published because of a Squidoo software glitch. I have a record of his comment but not of his name. Sorry about that. Here is your comment:
Hi Marc
Thanks for the great explanation. I have been reading a book about Einstein's life,
and obviously it includes relativity and all of his finding's, and I have become
quite obsessed with it... But just referring to the case of events not seeming
simultaneous to 2 observers with different velocities, which does make sense to me.
Surely though, one can calculate the "actual" time that an event occurs? I
understand that they may not "appear" to occur at the same time, but
surely there is a way to determine if they did occur at the same time? For example,
if we look at a star 1 million light years away, we would use logic to determine
that this is not where the star is NOW, but where it WAS 1 million years ago, and if
we had a record of an event that occured 1 million years ago, then these 2 events
would be simultaneous... would they not?
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Marc_Sandford
May 26, 2011 @ 9:26 am | delete
- My reply to above question:
Sure. There is no problem with this if the timing of the event and the star sighting were both made in the same frame of reference (on the earth say).
You can also use logic to determine the simultaneity of events that don't appear simultaneous such as when two stars explode. Someone living halfway between the two stars might see them both exploding at the same time. Someone else living closer to one star (and who is stationary relative to the first guy) would see it explode before the other star. Logic says that the person living halfway between the two stars would have the correct perception since the light from both stars traveled equal distances and arrived at the same time.
With the example you gave and with my example, simple logic works well. However, there are circumstances in which two observers can have different perceptions about simultaneity where there is no way that logic can favor one or the other. Any preference would be pure bias. This occurs when the two observers are moving rapidly relative to each other. Watch this video here and listen closely. Most people are inclined to favor the point of view of the person standing on the ground rather than the person inside the train. But there is no logical reason for this. It is pure bias. Think of the train as a rocket passing by. And the earth as just an oversized space ship. Why favor the person standing on the earth simply because the earth is big? If we bias our judgments on the basis of the size of the "space ship" then we should favor the perceptions of an alien living on Jupiter over our own here on earth. This of course is absurd. So there are circumstances where simultaneity is purely relative.
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rypier
May 5, 2011 @ 1:55 pm | delete
- Hi, I've been reading The Elegant Universe by Brian Greene. In the first few chapters he talks about relativity, I understand the basic ideas of it, but in the book it explained the time dilation to be caused from the passage of time that it takes from a signal to travel to a viewer. It gave an example of two astronauts floating past each other in space with synchronized clocks, then, after a year or so they communicate by phone and tell each other their time. The person receiving the signal would get it much later than it was sent because it would take a while for the signal to reach him, so according to the recipient, the other person's clock would be slow. However this is a faulty explanation because it would only work over great distances and not because of a person's relative speed. This has been bothering me for a while, could you give me a better explanation?
Thanks!
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Marc_Sandford
May 6, 2011 @ 7:22 am | delete
- The signal received by the 2nd guy gives the time that the signal was sent which of course is different from the time that it was received. If the first guy had kept sending time readings spaced one second apart, the second guy would have received each reading spaced one second apart (assuming there is little speed difference between the two people). If the speed difference between the two people was a significant fraction of the speed of light then the second guy would have received readings that were spaced more than one second apart even though the first guy (from his point of view) is sending time signals spaced one second apart. This difference in signal spacing is time dilation. As you correctly stated, time dilation is caused by the relative speed between the two people. For an explanation of dilation read the section called "Why time slows down" on this page. Also watch the Time Dilation Video on this page.
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Philippians468
Apr 14, 2011 @ 12:21 pm | delete
- such an important and interesting topic! thank you for sharing this! cheers
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Marc_Sandford
Apr 15, 2011 @ 7:16 am | delete
- You are most welcome!
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TheRatRaceRebel Apr 12, 2011 @ 10:55 am | delete
- OK, I know that the x-box is more popular than the theory of relativity but I think "Einstein's Special Theory of Relativity" should be in the top 100 here at Squidoo instead.
Very cool, insightful and helpful lens. Thanks for building it I'll be sending my daughter here when we get to this in our physics studies!
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Marc_Sandford
Apr 13, 2011 @ 6:38 am | delete
- I guess it's a supply and demand thing. What the people want, they will get. The Xbox is a good example of engineering gone wrong (among other things) and would make a good case study for engineering students.
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chithukkutty
Apr 2, 2011 @ 2:02 pm | delete
- I CHECKED THE INTERNET BUT I COULD NOT FIND ANY SATELLITE THAT IS COMMON TO BOTH THE EARTH AND THE MOON, IS THE EXISTENCE OF SUCH A SATELLITE POSSIBLE? CAN THE SYSTEM OF MASS THE EARTH AND THE MOON CAN ACT AS A SINGLE BODY HENCE SUPPORTING ANOTHER OBJECT AS A COMMON MOON?
THANK YOU VERY MUCH FOR YOUR SUPPORT IN ANSWERING MY QUESTIONS
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Marc_Sandford
Apr 2, 2011 @ 7:56 pm | delete
- Hi. I was talking about satellites that orbit just the earth and OTHER satellites that orbit just the moon. Don't know if any satellites are orbiting the moon right now but one of the later Apollo missions left a small satellite in orbit around the moon.
It wasn't clear to me that you meant a moon that orbited the mass center of the dual planet system. Short of doing an actual computer simulation, some simple reasoning would suggest that a moon could certainly orbit a dual planet system. If the dual planets were fairly massive and close together then their behavior wouldn't be affected much by a smaller and very distant body. This smaller distant body would gravitationally react to the dual planets as if they were a single mass concentrated at their mass center. So in principal, it is possible. I believe that planets have been found that have stable orbits around binary stars. It isn't too much of a stretch to say that some of these binary stars (with their orbiting planets) are in orbit around an even greater mass - the galactic center. This is evidence that two masses orbiting each other can have a third smaller mass orbiting about them and the whole kaboodle can be in orbit around an even greater mass.
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chithukkutty
Apr 3, 2011 @ 9:04 am | delete
- thank you soooooooooo soooooooooo much!!!!!!!!!!!!!!! :D
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chithukkutty
Mar 31, 2011 @ 10:34 pm | delete
- hey my Q is not about relativity , since you have given such beautiful answers to all those questions i hope i will get a reply to my question,
1) if two bodies, a 10kg metal ball, and a 1kg metal ball are floating in air, can the 10kg body due to its gravitation stabilize the position of the 1kg metal ball
another question is,
2) (i)can two planets, spinning on their own axis, and orbitting a common centre of mass, can orbit a star like our plant around the sun
(ii) if it can , can they have moons?
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Marc_Sandford
Apr 2, 2011 @ 9:15 am | delete
- 1.) Two bodies in space can orbit about a common point called the barycenter. As you can see here, the obital motion doesn't necessarily have to be like that of a smaller planet-like mass orbiting a hugely more massive body like a star.
2i.) Yes. At least two examples of that exist within our solar system. The earth and the moon (though moon isn't spinning but phase locked) are considered to be a double planet system with a barycenter located inside the earth and the Pluto-Charon system (I don't know whether either of them spin).
2ii) You entering an area called the n-body problem. Once you go beyond 2 bodies, the motion in general is chaotic in that their trajectories are extremely sensitive to what thier initial conditions are. Now, our solar system consists of more than just two bodies. However each planets interaction with the sun greatly overwhelms the effects of any weak interactins they have with each other. This means each planet almost (but not quite) behaves as if it were only part of a two body system consisting of itself and the sun. Each planet is peturbed slightly to varying degrees by the other planets. Another way that you can get approximate two-body behavior in an n-body system is to have two bodies in close proximity to each other so that the other distant bodies exert an almost negligible effect on how they orbit each other. A moon orbiting a planet is an example of this where the sun doesn't have nuch of an effect on how they orbit each other. Now that I've given you some theory, here is the answer your question: it is yes. How do I know? We have launched artificial satellites about the earth and about the moon. The moons mass is substantial compared to the earth so the earth and moon can be considered dual planets orbiting each other (with a center of mass in orbit around the sun). The earth and the moon in turn have artificial moons (satellites) in orbit around them.
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Marc_Sandford
Apr 2, 2011 @ 9:25 am | delete
- Forgot to put my answer through spell check but it shouldn't affect you ability to understand.
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Marc_Sandford
Apr 2, 2011 @ 9:30 am | delete
- ...and of course, there's a grammatical error in my spell check comment. Need some coffee now...
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Marc_Sandford
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