Solving Systems of Equations
This Lens explores the three ways to solve a system of equations in two variables. It includes various videos explaining examples and an explanation on how to use each method. Feel free to ask any specific questions in the comments section. Scroll down or use the Table of Contents to find the topics that interest you.
If you are a teacher looking for resoureces check out my math teaching website. There are some very good worksheets.
If you are a student and looking to get all of your math help in one place this math learning is for you.
Though I think this lens is valuable and can really help you understand systems of equations sometimes it isn't enough. One of the most effective ways to learn math is one on one tutoring. Tutor.com offers 25 minutes for FREE and is something you should check out.

If you are a teacher looking for resoureces check out my math teaching website. There are some very good worksheets.
If you are a student and looking to get all of your math help in one place this math learning is for you.
Though I think this lens is valuable and can really help you understand systems of equations sometimes it isn't enough. One of the most effective ways to learn math is one on one tutoring. Tutor.com offers 25 minutes for FREE and is something you should check out.
Video Learning
This page is designed around a series of videos I have created about systems of equations. The following is an example of one. You can either scroll down or use the table of contents to find the rest.
curated content from YouTube
Mr. T on the Web
- Polynomials
- A lens showing how to add, subtract, multiply and factor polynomials.
- Solving Quadratic Equations
- A lens showing how to solve quadratic equations.
- Solving Inequalities
- A lens on solving inequalities.
- Linear Inequalities
- A lens on solving linear inequalities.
- Exponent Properties
- A lens explaining the basic exponent properties of Algebra 1.
Solving Systems by Graphing
The solution to a system of equations is the ordered pair (x, y) that makes both equations true. For example (2, 3) is the solution of the system:
2x + y = 7
4x - 2y = 2
Because:
2(2) + 3 = 7
and
4(2) - 2(3) = 2
It is also important to remember that the graph of a linear equation consists of all the points that make that equation true.
Thus to solve a system of equations by graphing you find the point where the two lines intersect. Because this point is on both lines it thus makes both equations true. So the intersection point represpents the solution to the system of equations.
Special Cases
1) The lines are parallel to each other - By definition two lines that are parallel never intersect each other. Thus they have no points in common and as a result we say the answer is "no solution". The best way to confirm this result is to put both equation in slope intercept form (y = mx + b). If the slopes are the same and the y - intercepts are different then the lines are parallel.
2) The lines are the same - Occasionally the two equations will look different but actually be the exact same line. When you graph them you will notice that they are the exact same line. As with before the simplest way to determine this is to put both equations in slope intercept form.
Some Other Things to Consider
1) Graphing by hand is not very precise. Thus occasionally it is difficult to determine the exact solution. If an exact solution is necessary then it would be best to use one of the other methods described below.
2) If you are having trouble graphing then check out some of the links below. I will be designing a lens on graphing, but it will be a few months before it is done. I primarily use the slope-intercept method and then x, y - intercept method.
2x + y = 7
4x - 2y = 2
Because:
2(2) + 3 = 7
and
4(2) - 2(3) = 2
It is also important to remember that the graph of a linear equation consists of all the points that make that equation true.
Thus to solve a system of equations by graphing you find the point where the two lines intersect. Because this point is on both lines it thus makes both equations true. So the intersection point represpents the solution to the system of equations.
Special Cases
1) The lines are parallel to each other - By definition two lines that are parallel never intersect each other. Thus they have no points in common and as a result we say the answer is "no solution". The best way to confirm this result is to put both equation in slope intercept form (y = mx + b). If the slopes are the same and the y - intercepts are different then the lines are parallel.
2) The lines are the same - Occasionally the two equations will look different but actually be the exact same line. When you graph them you will notice that they are the exact same line. As with before the simplest way to determine this is to put both equations in slope intercept form.
Some Other Things to Consider
1) Graphing by hand is not very precise. Thus occasionally it is difficult to determine the exact solution. If an exact solution is necessary then it would be best to use one of the other methods described below.
2) If you are having trouble graphing then check out some of the links below. I will be designing a lens on graphing, but it will be a few months before it is done. I primarily use the slope-intercept method and then x, y - intercept method.
Important!
Don't Forget!!!
The solution to a system of equations is the point (x,y) that makes both equations true.
Tell Me About Yourself!!!
Loading poll. Please Wait...
What Every High School Student Needs
A graphing calculator is becoming an essential part of high school math classrooms. They not only help in solving problems but they can help you visualize things as well. Ebay is the best place to purchase quality graphing calculators for cheap. TI-84 are the most commonly used.
Solving Systems of Equations by Substitution
The solution to a system of equations is the ordered pair that makes both equations true. One way to discover this point is to use a method called substitution. There are 4 very specific steps that are followed when using this method.
Procedure
1) Solve one of the equations for one of the variables (occasionally this is done for you). Usually you want to solve for the variable that is the easiest. For instance if the equation is 3x + y = 12 then you should solve for y because it does not have a coefficient. Solving for x would mean you would have to divide everything by three.
2) Look at the other equation, it should contain the variable you just solved for. The next step is to substitute for that variable what it equaled when you solved for it. This is accomplished by "replacing" the variable with the expression it equals. There should only be one variable remaining in the new equation.
3) Solve the new equation for the variable that is remaining. This will usually involve performing the distributive property first.
4) Subsitute that value into one of the two original equations and solve for the other variable.
The following examples show these four steps in action. The only thing that varies is step one. Steps 2 through 4 are pretty much the same everytime. At the end of each example the solution is checked. This is a very, very good habit to get into.
Procedure
1) Solve one of the equations for one of the variables (occasionally this is done for you). Usually you want to solve for the variable that is the easiest. For instance if the equation is 3x + y = 12 then you should solve for y because it does not have a coefficient. Solving for x would mean you would have to divide everything by three.
2) Look at the other equation, it should contain the variable you just solved for. The next step is to substitute for that variable what it equaled when you solved for it. This is accomplished by "replacing" the variable with the expression it equals. There should only be one variable remaining in the new equation.
3) Solve the new equation for the variable that is remaining. This will usually involve performing the distributive property first.
4) Subsitute that value into one of the two original equations and solve for the other variable.
The following examples show these four steps in action. The only thing that varies is step one. Steps 2 through 4 are pretty much the same everytime. At the end of each example the solution is checked. This is a very, very good habit to get into.
What is your favorite way to solve systems of equations.
Loading poll. Please Wait...
Amazon Items
A graphing calculator is an essential tool for a high school math student. You can get by without it in Algebra 1, but when you get to Algebra 2, PreCalculus and Calculus it becomes very important. The following calculators are the most common used and Amazon has them at a very good price.
Solving Systems Equations by Elimination
We have learned two methods for solving systems of equations. Graphing and subsitution. The goal of subsitution was to put the equations together in such a way that there was only one variable left. This allowed us to solve for the variable. The elimination method is similar. Our goal is to eliminate one of the variables by adding the two equations together. Consider the following two equations:
x + y = 12
-x +3y = 4
If we add these together vertically:
x + y = 12
So by adding the two equations together we eliminated the x variable. The key is that in both equations the x variable had the same coefficient (1) just an opposite sign. Thus when they are added together the coefficient of x is zero.
So with this in mind we break elimination down to the following steps.
1) The first step is to manipulate the equations such that one of the two variables will be eliminated.
2) Add the two equation together to get one equation with one variable.
3) Solve the new equation for the remaining variable.
4) Plug that value in for the variable in one of the two remaining equations and then solve for the other variable.
If you notice, steps 2-4 are very similar to steps 2-4 when using substitution. The key step is to multiply the original equations in a way that allows the variable to be eliminated when the two equations are added together.
x + y = 12
-x +3y = 4
If we add these together vertically:
x + y = 12
+-x + 3y = 4
=0x + 4y = 16So by adding the two equations together we eliminated the x variable. The key is that in both equations the x variable had the same coefficient (1) just an opposite sign. Thus when they are added together the coefficient of x is zero.
So with this in mind we break elimination down to the following steps.
1) The first step is to manipulate the equations such that one of the two variables will be eliminated.
2) Add the two equation together to get one equation with one variable.
3) Solve the new equation for the remaining variable.
4) Plug that value in for the variable in one of the two remaining equations and then solve for the other variable.
If you notice, steps 2-4 are very similar to steps 2-4 when using substitution. The key step is to multiply the original equations in a way that allows the variable to be eliminated when the two equations are added together.
Solving Systems of Equations by Elimination Example 5
These two problems are examples of elimination where both variables are eliminated. The result is one of two things.
1) a = a Where a is a real number. Essentially you are looking for the equation to be true - When this happens the answer is "All Solutions" or something similar. It means that every ordered pair that is a solution to one of the equations is a solution to the other. If you solved both equations for "y" you would discover they are the same equation.
2) 0 = (A # other than zero). This time you are looking for an equation that is not true. When this happens the answer is "no solution." Which means an ordered pair that is the solution to one of the equations would not be the solution to the other equation. This also means that the lines are parallel.
1) a = a Where a is a real number. Essentially you are looking for the equation to be true - When this happens the answer is "All Solutions" or something similar. It means that every ordered pair that is a solution to one of the equations is a solution to the other. If you solved both equations for "y" you would discover they are the same equation.
2) 0 = (A # other than zero). This time you are looking for an equation that is not true. When this happens the answer is "no solution." Which means an ordered pair that is the solution to one of the equations would not be the solution to the other equation. This also means that the lines are parallel.
curated content from YouTube
Another Special Case
This is another look at special cases of systems of equations.
curated content from YouTube
Other Websites Discussing Systems of Equations
- Purple Math
- A good look at solving systems of equations by graphing.
- Word Problems
- A good website discussing word problems involving systems of equations.
Here are some other recommendations
If you loved Texas Instruments TI-84 Plus Graphing Calculator, you might also enjoy:
TI-84 Plus Graphing Calculator for Dummies by C. C. Edwards
If you have a T1-84 Plus Graphing Calculator, you more...0 points
Texas Instruments TI-84 Plus Silver Edition Graphing Calculator
Texas Instruments TI-84 Plus Silver Edition Graphi more...0 points
Texas Instruments TI-30X IIS 2-Line Scientific Calculator
A calculator for science, math, algebra, trigonome more...0 points
New Guestbook
submit
-
Reply
-
Tabooni
Oct 27, 2011 @ 10:29 pm | delete
- nice lens
-
-
Reply
-
chilldusty18cool
Jul 24, 2011 @ 7:31 am | delete
- Its good to read this lense.Thanks for sharing it.
Review
-
-
Reply
-
chilldusty18cool
Jul 17, 2011 @ 9:11 am | delete
- Its good to read this lense.Thanks for sharing it.
Jay Discount
Review JK
-
-
Reply
-
factoringexpert
Jun 15, 2011 @ 10:57 am | delete
- Excellent lens! If only we had this back when we were in school.
ifgnetwork.co.uk
-
-
Reply
-
factoringexpert
Jun 15, 2011 @ 10:54 am | delete
- Excellent lens! If only we had this back when we were in school.
http://www.ifgnetwork.co.uk
-
-
Reply
-
blackspanielgallery
Feb 27, 2011 @ 1:25 am | delete
- Using a TI-83 or TI-84, you can solve nonlinear systems using the intersect technique.
-
-
Reply
-
Dec 22, 2010 @ 12:27 am | delete
- jordan flight 45 high white black Cheap Nike Shox Shoes On Sale! basketball shoes shopcheap Air jordan shoes. cheap Jordan Sneakers. cheap kids jordans. Air Jordan Sneakers.HiJordan is a professional store sells Air Jordan Shoes with the best quality and nike basketball shoes jordan shoes supra shoes timberland ugg boots nike air force one all are very cheap in easyforbuy online store, retro nike basketball shoes buy now! mens nike basketball shoes.Cheap Jordans|Jordan Shoes for sale. We sale new Nike shoes,Air Jordan Sneakers,Nike Air Force 1,Nike Dunk SB,Nike Shox from Nike outlets and factory stores.Air Jordan Shoe online store. Discount Jordans with cheap price retro air jordans We offer Wholesale Nike Jordan and Cheap Air Jordan Shoes,Air Force One,Air Max, Nike Air Jordans Shoes, Nike Air Max Shoes, Nike Air Force Shoes air jordan basketball shoes Authentic Nike Air Jordan Retro for Sell
-
-
Reply
-
Nov 2, 2010 @ 2:45 am | delete
- Thanks to share great lens!
Business Coaching
-
-
Reply
-
Aug 30, 2010 @ 10:30 am | delete
- Thanks to share great information!
I would like to let you know, Tutoring Services LLC. offers opportunity of online tutoring jobs with free registration for tutors.
-
-
Reply
-
yuki
Jul 16, 2008 @ 6:10 am | delete
- thanks for all the effort!!
I completely understood it!
-
- Load More
by MrT68
MrT68
My name is Trent Tormoehlen and I am a math teacher at Sycamore School in Indianapolis Indiana. I will also be helping coach the schools Math Counts... more »
- 9 featured lenses
- Winner of 5 trophies!
- Top lens » Basic Exponent Properties
Feeling creative?
Create a Lens!
Explore related pages
- Kumon Math Review Kumon Math Review
- 10 Fun Math Games and Activities 10 Fun Math Games and Activities
- Online Math Homework Help for Kids Online Math Homework Help for Kids
- Gallon Man Teaches Liquid Measurement Gallon Man Teaches Liquid Measurement
- I Love Teaching Math I Love Teaching Math
- Linear Inequalities Linear Inequalities





